This 'question' is about laser beam spot sizes and plano-convex (or positive meniscus) lens focal lengths. I got the formulas off the www and got some pretty weird answers, so I have tried to think and answer the first part and provide examples to show my work as it were. The last part, I cannot answer. Anyone know optics well?
This is long, but it makes sense and the math was not bad.
I used two examples, a HeNe laser and CO2, because the big difference in wavelengths seems to have a real effect on spot size when the focal lengths get long. Anyone care to comment?
A laser beam - due to diffraction and beam divergence which in turn are related to dimensions being finite - will focus to a spot size that is directly proportional to the focal length of the lens and inversely proportional to the diameter of the laser beam at the point it meets the lens. The formula is:
spot dia. = 1.27 x f x wavelength x M^2 / D
where
f is lens focal length,
D is the beam diameter at lens position (generally smaller than the lens diameter),
and
M^2 is a number indicating the beam diffraction and divergence, I am assuming "1" that is to assume a perfect Gaussian beam profile.
In the CO2 laser, the wavelength is 10.6 micron (0.0106mm), so the above relation:
spot dia. = 1.27 x 0.0106 x M^2 x f / D
becomes;
spot dia. (in mm) = 0.013 x M2 x f / D
It could be any wavelength of laser, green, red, does not matter..) All units in mm.
With a f = 100 mm (4 inch) focal length lens and a beam diameter of 6 mm we get (assume M^2=1 in every case)
spot size (in mm) = .013 x 100/6 = 0.2 mm = 200 micron
for beam dia 2mm we get:
spot size (in mm) = .013 x 100/2 = 0.5 mm = 500 micron
The smaller beam diameter made the bigger spot!
now how about this:
I use a lens with a 2000mm focal length - I theoretically want to focus the 2mm beam about 7 ft away from the laser.
spot dia. (in mm) = 0.013 x M^2 x f / D
spot dia. (in mm) = 0.013 x f / D
spot dia. (in mm) = 0.013 x 2000 / 2
spot dia. (in mm) = 0.013 x 1000 = 13mm ??
How did the 2mm diameter pass through a plano-convex focusing lens and get focused to a huge 13mm spot at the focal point?
That did not make sense to me so I considered another wavelength, 635nm of the HeNe laser..
-->OK run the numbers for 635nm helium neon with a 2mm beam diameter. I know the beam is usually smaller, like 0.2mm, but for the sake of the argument.
spot dia. = 1.27 x f x wavelength x M^2 / D
In the 635nm laser, the wavelength is 0.635 micron (0.000635mm), so the above relation:
spot dia. = 1.27 x 0.000635 x M^2 x f / D
becomes;
spot dia. (in mm) = 0.00080645 x M2 x f / D
With a f = 100 mm (4 inch) focal length lens and a beam diameter of 2 mm we get (assume M^2=1 in every case)
spot size (in mm) = 0.00080645 x 100/2 = 0.040325 mm = 40 micron
(In the CO2 example with a 2mm beam and a 100mm lens, the spot diameter was 500 microns)
now how about this:
I use a lens with a 2000mm focal length - right I theoretically want to focus the 2mm beam about 7 ft away from the laser.
spot dia. (in mm) = 0.00080645 x M^2 x f / D
spot dia. (in mm) = 0.00080645 x f / D
spot dia. (in mm) = 0.00080645 x 2000 / 2
spot dia. (in mm) = 0.00080645 x 1000 = 0.8mm ??
So, with this long 2 meter focal length, the 2mm beam is only reduced to 0.8mm. It is still much smaller than with the same lens and beam diameter applied to a CO2 laser, the difference in the final spot size being related to the wavelength.
Can we use some kind of obscene lens that will ruin (not-focus) the HeNe beam diameter just like with the CO2 laser?
a 20 meter focal length for the same HeNe laser:
Lens is not likely to exist but:
spot dia. (in mm) = 0.00080645 x 20000 / 2 = 8.0645
--> yes a 2mm HeNe beam becomes an 8mm beam at the 20-meter focal point of a convex lens.
Experts: Have I done the math right? Is this a sad truth about trying to be cheap on optics when focusing lasers at long distances?
Next - a 10x collimator.
Back to the CO2 laser and its huge wavelength. If a collimator is used to spread the beam to 20mm, and then the 2000mm focusing lens is used:
spot dia. (in mm) = 0.013 x M^2 x f / D
spot dia. (in mm) = 0.013 x f / D
spot dia. (in mm) = 0.013 x 2000 / 20
spot dia. (in mm) = 0.013 x 100 = 0.13mm
nice.. good for the engraver.
Apply it to the HeNe laser:
spot dia. (in mm) = 0.00080645 x M^2 x f / D
spot dia. (in mm) = 0.00080645 x f / D
spot dia. (in mm) = 0.00080645 x 2000 / 20
spot dia. (in mm) = 0.00080645 x 100 = 0.08mm
It is easy to see that the 20000mm lens would still provide a 0.8mm spot for the HeNe laser.
This also explains why the YAG laser here has only been able to be focused to about 1.5mm with a 4000mm plano-convex lens.
i still don't get just how a beam can be made larger at a focal point than it is going in.. Is there a fault in the formula?
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Next question, and I have not tried to answer this one because this is still confusing to me:
What is the relationship of how far from the collimator's 20mm output the 2000mm focal length lens is placed?
The reason I ask about the collimator is because all I see is blowing up the beam, only to turn around and reduce it, and I've been told you can't get a free lunch.